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WAEC Past Questions Chemistry: Detailed Solutions & Free Practice (2027)

By SchoolHub Team6 September 202630 min read

WAEC Past Questions Chemistry: Detailed Solutions & Free Practice (2027)

Student studying chemistry with periodic table and laboratory equipment

Introduction: Why Chemistry Requires a Three-Pronged Approach

Chemistry is a compulsory subject for candidates pursuing Medicine, Pharmacy, Engineering, Biochemistry, Industrial Chemistry, Agricultural Science, and most science-related university programmes. A credit in Chemistry (C6 or above) is a strict requirement, and many competitive programmes demand B3 or higher.

What makes WAEC Chemistry uniquely challenging is that it demands three distinct skill sets simultaneously. First, you need conceptual understanding: knowing why reactions happen, what determines the rate of a reaction, and how atomic structure influences chemical behaviour. Second, you need calculation skills: stoichiometry, molar mass, concentration, gas volume, and enthalpy calculations require mathematical precision. Third, you need memorisation: chemical equations, IUPAC nomenclature, periodic table trends, reagents and observations for qualitative analysis, and functional group reactions must be committed to memory.

Candidates who prepare for only one or two of these dimensions consistently underperform. The student who understands concepts but cannot balance equations will lose marks. The student who memorises equations but cannot calculate moles will lose marks. The student who can calculate but does not know the tests for gases and ions will lose marks on the practical/alternative-to-practical paper.

The candidates who score A1 to B3 in WAEC Chemistry are the ones who build all three skills systematically and practise with past questions under timed conditions.

This guide breaks down the WAEC Chemistry syllabus, gives you 25 practice questions with detailed solutions, provides essential equations and constants, and maps out a study plan for a strong grade.

Start Practising Now: SchoolHub's Free JAMB CBT Practice App includes Chemistry questions that build the same skills tested in WAEC, completely free.


WAEC Chemistry at a Glance

AspectDetail
PapersPaper 1 (Objective), Paper 2 (Essay/Theory), Paper 3 (Alternative to Practical / Practical)
Paper 1 format50 multiple-choice questions; 1 hour
Paper 2 formatTheory questions (answer any 5 from about 8); 1 hour 30 minutes
Paper 3 formatPractical or Alternative to Practical; 2 hours
GradingA1 (Excellent) to F9 (Fail)
Minimum for university admissionC6 or above for most science programmes
Syllabus sourceWAEC Chemistry Syllabus (current edition)
Recommended textbooksNew School Chemistry by Osei Yaw Ababio; Comprehensive Certificate Chemistry by G.N.C. Ohia; Essential Chemistry by M.A. Odesina

Complete WAEC Chemistry Syllabus Breakdown

1. Separation Techniques and Purification (4%)

  • Methods: filtration, evaporation, crystallisation, distillation (simple and fractional), chromatography, sublimation, separating funnel, centrifugation, magnetism
  • Criteria for purity: melting point, boiling point
  • Physical and chemical changes

2. Chemical Combination and Stoichiometry (10%)

  • Laws of chemical combination: conservation of mass, definite proportions, multiple proportions
  • Dalton's atomic theory
  • Chemical symbols, formulas, and equations
  • Balancing chemical equations
  • Mole concept: Avogadro's number (6.02 x 10^23)
  • Molar mass, molar volume of gases (22.4 dm^3 at STP)
  • Stoichiometric calculations: reacting masses, gas volumes, solution concentrations
  • Empirical and molecular formulas
  • Percentage composition

3. Atomic Structure and Bonding (10%)

  • Structure of the atom: protons, neutrons, electrons
  • Atomic number, mass number, isotopes
  • Electronic configuration (s, p, d notation and spdf)
  • Periodic table: periods, groups, trends (atomic radius, ionisation energy, electronegativity, electron affinity)
  • Types of bonding: ionic, covalent (single, double, triple), metallic, coordinate (dative), hydrogen bonding, van der Waals forces
  • Properties related to bond type
  • Shapes of simple molecules (VSEPR concept)

4. States of Matter and Gas Laws (8%)

  • Kinetic theory of matter
  • Properties of solids, liquids, and gases
  • Changes of state: melting, boiling, evaporation, condensation, sublimation
  • Gas laws: Boyle's, Charles's, combined gas law, Dalton's law of partial pressures, Graham's law of diffusion
  • Ideal gas equation: PV = nRT

5. Acids, Bases, and Salts (10%)

  • Definitions: Arrhenius, Bronsted-Lowry, Lewis
  • Properties of acids and bases
  • pH scale and indicators
  • Strong and weak acids/bases
  • Neutralisation reactions
  • Types of salts: normal, acidic, basic, double, complex
  • Preparation of salts: neutralisation, precipitation, direct combination
  • Solubility and solubility curves
  • Hydrolysis of salts

6. Redox Reactions and Electrochemistry (10%)

  • Oxidation and reduction: electron transfer, oxidation states
  • Balancing redox equations using oxidation states
  • Oxidising and reducing agents
  • Electrochemical cells: galvanic (voltaic) cells
  • Electrolysis: Faraday's laws, applications
  • Calculations involving Faraday's laws
  • Electrochemical series and its applications
  • Corrosion and its prevention

7. Energy and Chemical Reactions (8%)

  • Exothermic and endothermic reactions
  • Enthalpy changes: heat of reaction, heat of formation, heat of combustion, heat of neutralisation, heat of solution
  • Hess's law of constant heat summation
  • Bond energy calculations
  • Energy diagrams (energy profile diagrams)

8. Rates of Chemical Reactions and Equilibrium (8%)

  • Factors affecting rate: concentration, temperature, pressure, surface area, catalyst
  • Collision theory
  • Activation energy and catalysts
  • Chemical equilibrium: dynamic equilibrium, Le Chatelier's principle
  • Equilibrium constant (Kc) and its calculation
  • Factors affecting equilibrium position

9. Non-metals and Their Compounds (8%)

  • Hydrogen: preparation, properties, uses
  • Oxygen: preparation, properties, uses, oxides (acidic, basic, amphoteric, neutral)
  • Water: hardness, softening, treatment
  • Carbon and its allotropes: diamond, graphite, fullerenes
  • Carbon dioxide and carbon monoxide
  • Nitrogen and its compounds: ammonia (Haber process), nitrogen oxides, nitric acid (Ostwald process)
  • Sulphur and its compounds: SO2, SO3, H2SO4 (Contact process)
  • Halogens: chlorine, HCl, properties and trends down the group

10. Metals and Their Compounds (8%)

  • General properties of metals
  • Reactivity series and its applications
  • Extraction of metals: aluminium (electrolysis), iron (blast furnace)
  • Alloys: steel, brass, bronze
  • Corrosion of iron and prevention methods
  • Transition metals: properties, coloured compounds, variable oxidation states, catalytic activity
  • Compounds of sodium, calcium, aluminium, iron

11. Organic Chemistry (12%)

  • Carbon and its unique properties (catenation, tetravalency)
  • Hydrocarbons:
    • Alkanes: nomenclature, properties, reactions (combustion, substitution)
    • Alkenes: nomenclature, properties, reactions (addition, polymerisation)
    • Alkynes: nomenclature, properties
    • Benzene: structure, properties
  • Functional groups:
    • Alcohols (alkanols): nomenclature, properties, fermentation, dehydration
    • Carboxylic acids (alkanoic acids): nomenclature, properties, esterification
    • Esters (alkyl alkanoates): preparation, hydrolysis, uses
    • Amines, amides
  • Petrochemicals: fractional distillation of crude oil, cracking, reforming
  • Polymers: addition and condensation polymerisation
  • Fats and oils, soaps and detergents, proteins, carbohydrates

12. Industrial Chemistry (4%)

  • Industrial processes: Haber process, Contact process, Solvay process
  • Environmental pollution: air, water, soil
  • Greenhouse effect and climate change
  • Biotechnology and fermentation

Essential Constants and Equations

Key Constants

ConstantValue
Avogadro's number6.02 x 10^23 mol^-1
Molar volume at STP22.4 dm^3
Molar volume at room temperature24.0 dm^3
Faraday's constant96,500 C/mol
Gas constant (R)8.314 J/(mol.K)
Standard temperature273 K (0 degrees C)
Standard pressure1 atm = 101,325 Pa = 760 mmHg

Essential Calculation Formulas

FormulaPurpose
Number of moles = mass / molar massFinding moles from mass
Number of moles = volume (dm^3) / molar volumeFinding moles of gas
Number of moles = concentration (mol/dm^3) x volume (dm^3)Finding moles from solution
Concentration (mol/dm^3) = moles / volume (dm^3)Finding molarity
Concentration (g/dm^3) = mass of solute (g) / volume of solution (dm^3)Finding mass concentration
PV = nRTIdeal gas equation
Percentage composition = (mass of element / molar mass) x 100Finding percentage by mass
Empirical formulaRatio of atoms in simplest form
Q = ItCharge in electrolysis
Mass deposited = (Q x M) / (n x F)Faraday's law calculation
Enthalpy change = sum of bond energies broken - sum of bond energies formedBond energy enthalpy

Qualitative Analysis: Common Tests

Test ForReagent/MethodObservation
Hydrogen gasBurning splintBurns with a pop sound
Oxygen gasGlowing splintRelights the glowing splint
Carbon dioxideLime water (Ca(OH)2)Turns milky/cloudy
Chlorine gasDamp litmus paperBleaches (turns white)
Ammonia gasDamp red litmus paperTurns blue
Sulphur dioxideAcidified K2Cr2O7Turns from orange to green
StarchIodine solutionTurns blue-black
Cl- ionDilute HNO3 + AgNO3White precipitate (soluble in NH3)
SO4^2- ionDilute HCl + BaCl2White precipitate (insoluble in HCl)
CO3^2- ionDilute HClEffervescence; gas turns lime water milky
Fe^2+ ionNaOH solutionDirty green precipitate
Fe^3+ ionNaOH solutionReddish-brown precipitate
Cu^2+ ionNaOH solutionLight blue precipitate
Zn^2+ ionNaOH solution (excess)White precipitate, dissolves in excess
Al^3+ ionNaOH solution (excess)White precipitate, dissolves in excess
Pb^2+ ionNaOH solution (excess)White precipitate, dissolves in excess

25 WAEC Chemistry Practice Questions With Solutions

Atomic Structure and Bonding

Question 1 An element has the electronic configuration 1s^2 2s^2 2p^6 3s^2 3p^5. The element is:

Options: A. A metal in Group II B. A non-metal in Group VII C. A noble gas D. A transition metal

Answer: B

Solution: The total number of electrons is 2+2+6+2+5 = 17, which is the atomic number of chlorine (Cl). The outermost shell (3rd shell) has 7 electrons (3s^2 3p^5), placing the element in Group VII (the halogens). Chlorine is a non-metal.


Question 2 Which type of bond is formed between sodium (Na) and chlorine (Cl)?

Options: A. Covalent bond B. Ionic bond C. Metallic bond D. Hydrogen bond

Answer: B

Solution: Sodium is a metal (Group I) with low electronegativity, and chlorine is a non-metal (Group VII) with high electronegativity. The large difference in electronegativity means sodium transfers its outer electron to chlorine, forming Na+ and Cl- ions held together by electrostatic attraction. This is an ionic bond.


Stoichiometry and Mole Calculations

Question 3 What is the mass of 0.5 moles of calcium carbonate (CaCO3)? (Ca = 40, C = 12, O = 16)

Options: A. 25 g B. 50 g C. 75 g D. 100 g

Answer: B

Solution: Molar mass of CaCO3 = 40 + 12 + 3(16) = 40 + 12 + 48 = 100 g/mol Mass = moles x molar mass = 0.5 x 100 = 50 g


Question 4 What volume of carbon dioxide (at STP) is produced when 10 g of CaCO3 is completely decomposed? CaCO3 -> CaO + CO2 (Ca = 40, C = 12, O = 16)

Options: A. 1.12 dm^3 B. 2.24 dm^3 C. 11.2 dm^3 D. 22.4 dm^3

Answer: B

Solution: Molar mass of CaCO3 = 100 g/mol Moles of CaCO3 = 10/100 = 0.1 mol From the equation, 1 mol CaCO3 produces 1 mol CO2 So 0.1 mol CaCO3 produces 0.1 mol CO2 Volume at STP = 0.1 x 22.4 = 2.24 dm^3


Question 5 A compound contains 40% carbon, 6.7% hydrogen, and 53.3% oxygen by mass. What is its empirical formula? (C = 12, H = 1, O = 16)

Options: A. CHO B. CH2O C. C2H4O2 D. CH3O

Answer: B

Solution: Divide each percentage by the atomic mass: C: 40/12 = 3.33 H: 6.7/1 = 6.7 O: 53.3/16 = 3.33 Divide by the smallest (3.33): C: 3.33/3.33 = 1 H: 6.7/3.33 = 2 O: 3.33/3.33 = 1 Empirical formula = CH2O


Acids, Bases, and Salts

Question 6 What volume of 0.1 mol/dm^3 NaOH is required to completely neutralise 25 cm^3 of 0.2 mol/dm^3 HCl?

Options: A. 12.5 cm^3 B. 25.0 cm^3 C. 50.0 cm^3 D. 100.0 cm^3

Answer: C

Solution: NaOH + HCl -> NaCl + H2O (mole ratio 1:1) Moles of HCl = 0.2 x 25/1000 = 0.005 mol Moles of NaOH needed = 0.005 mol Volume of NaOH = moles / concentration = 0.005 / 0.1 = 0.05 dm^3 = 50.0 cm^3


Question 7 Which of the following is a strong acid?

Options: A. Ethanoic acid (CH3COOH) B. Carbonic acid (H2CO3) C. Sulphuric acid (H2SO4) D. Citric acid

Answer: C

Solution: Sulphuric acid (H2SO4) is a strong acid because it dissociates completely in water. Ethanoic acid (vinegar) is a weak organic acid. Carbonic acid (in fizzy drinks) is a weak acid. Citric acid (in citrus fruits) is also a weak acid. The common strong acids are HCl, H2SO4, and HNO3.


Redox and Electrochemistry

Question 8 In the reaction: Zn + CuSO4 -> ZnSO4 + Cu, which substance is oxidised?

Options: A. Zn B. CuSO4 C. ZnSO4 D. Cu

Answer: A

Solution: Zinc (Zn) is oxidised because it loses electrons: Zn -> Zn^2+ + 2e- Its oxidation state increases from 0 to +2. Copper (Cu^2+) is reduced because it gains electrons: Cu^2+ + 2e- -> Cu. Zinc is the reducing agent and copper sulphate contains the oxidising agent (Cu^2+).


Question 9 During the electrolysis of concentrated sodium chloride solution (brine), what is produced at the anode?

Options: A. Sodium metal B. Hydrogen gas C. Chlorine gas D. Oxygen gas

Answer: C

Solution: At the anode (positive electrode), chloride ions are discharged (oxidised): 2Cl- -> Cl2 + 2e-. Chlorine gas is produced. At the cathode, hydrogen gas is produced (from water, since sodium is too reactive to be discharged): 2H2O + 2e- -> H2 + 2OH-. Sodium hydroxide solution remains.


Question 10 How many grams of copper are deposited when a current of 5 A flows through a solution of CuSO4 for 1930 seconds? (Cu = 64, F = 96,500 C/mol)

Options: A. 1.6 g B. 3.2 g C. 6.4 g D. 12.8 g

Answer: B

Solution: Charge (Q) = I x t = 5 x 1930 = 9,650 C Cu^2+ + 2e- -> Cu (n = 2 electrons per atom) Mass = (Q x M) / (n x F) = (9650 x 64) / (2 x 96500) = 617,600 / 193,000 = 3.2 g


Energy Changes

Question 11 The enthalpy change for an exothermic reaction is:

Options: A. Positive B. Negative C. Zero D. Infinite

Answer: B

Solution: In an exothermic reaction, heat is released to the surroundings. The products have less energy than the reactants, so the enthalpy change (delta H) is negative. In an endothermic reaction, heat is absorbed, and delta H is positive.


Question 12 Given: C + O2 -> CO2, delta H = -393 kJ/mol CO + 1/2 O2 -> CO2, delta H = -283 kJ/mol Calculate the enthalpy of formation of CO.

Options: A. -110 kJ/mol B. +110 kJ/mol C. -676 kJ/mol D. +676 kJ/mol

Answer: A

Solution: Using Hess's law: the enthalpy change for C + 1/2 O2 -> CO can be found by subtracting the second equation from the first. delta H (formation of CO) = delta H1 - delta H2 = (-393) - (-283) = -393 + 283 = -110 kJ/mol


Rates and Equilibrium

Question 13 Which of the following would increase the rate of a chemical reaction?

Options: A. Decreasing the temperature B. Decreasing the concentration of reactants C. Adding a catalyst D. Increasing the volume of the container for a gaseous reaction

Answer: C

Solution: A catalyst increases the rate of reaction by lowering the activation energy, providing an alternative reaction pathway. Decreasing temperature slows reactions (particles have less kinetic energy). Decreasing concentration reduces the frequency of collisions. Increasing volume decreases pressure and concentration for gaseous reactions.


Question 14 For the equilibrium reaction: N2 + 3H2 <=> 2NH3 (delta H = -92 kJ/mol), which condition favours the formation of ammonia?

Options: A. High temperature and high pressure B. Low temperature and high pressure C. High temperature and low pressure D. Low temperature and low pressure

Answer: B

Solution: By Le Chatelier's principle: (1) The forward reaction is exothermic (delta H is negative), so low temperature favours the forward reaction. (2) There are 4 moles of gas on the left (1 + 3) and 2 moles on the right, so high pressure favours the side with fewer gas moles (the product side). Therefore, low temperature and high pressure favour ammonia production.


Gas Laws

Question 15 A gas occupies 500 cm^3 at 27 degrees C and 700 mmHg. What is its volume at STP?

Options: A. 388 cm^3 B. 420 cm^3 C. 480 cm^3 D. 550 cm^3

Answer: B

Solution: Using P1V1/T1 = P2V2/T2 P1 = 700 mmHg, V1 = 500 cm^3, T1 = 27 + 273 = 300 K P2 = 760 mmHg, T2 = 273 K V2 = P1V1T2 / (T1P2) = (700 x 500 x 273) / (300 x 760) V2 = 95,550,000 / 228,000 = 419 cm^3 (approximately 420 cm^3)


Non-metals

Question 16 In the Haber process, ammonia is produced from:

Options: A. Nitrogen and oxygen B. Nitrogen and hydrogen C. Ammonia and water D. Nitrogen and chlorine

Answer: B

Solution: The Haber process: N2 + 3H2 <=> 2NH3 Nitrogen is obtained from the fractional distillation of liquid air. Hydrogen is obtained from the reaction of methane with steam or from the cracking of hydrocarbons. Conditions: 450 degrees C, 200 atm pressure, iron catalyst.


Question 17 The gas produced when dilute hydrochloric acid is added to a carbonate is:

Options: A. Hydrogen B. Oxygen C. Carbon dioxide D. Chlorine

Answer: C

Solution: When acid reacts with a carbonate, carbon dioxide gas is produced along with water and a salt: CaCO3 + 2HCl -> CaCl2 + H2O + CO2 The CO2 can be confirmed by passing it through lime water, which turns milky.


Metals

Question 18 Iron is extracted from its ore in the blast furnace. The main reducing agent is:

Options: A. Hydrogen B. Carbon monoxide C. Carbon dioxide D. Limestone

Answer: B

Solution: In the blast furnace, carbon monoxide (CO) is the main reducing agent that reduces iron(III) oxide to iron: Fe2O3 + 3CO -> 2Fe + 3CO2 Carbon (coke) burns to form CO2, which then reacts with more coke to form CO. Limestone is added as a flux to remove impurities (forming slag), not as a reducing agent.


Organic Chemistry

Question 19 What is the IUPAC name of CH3CH2CH2OH?

Options: A. Methanol B. Ethanol C. Propan-1-ol D. Propan-2-ol

Answer: C

Solution: The molecule has 3 carbon atoms (propane backbone) with an -OH group on carbon 1. Following IUPAC naming: the parent chain is propane, the functional group is -ol (alcohol), and its position is carbon 1. The name is propan-1-ol. Propan-2-ol would be CH3CH(OH)CH3.


Question 20 Ethene reacts with bromine water to form:

Options: A. Ethane B. 1,2-dibromoethane C. Bromoethane D. Ethanol

Answer: B

Solution: Ethene (CH2=CH2) undergoes an addition reaction with bromine: CH2=CH2 + Br2 -> CH2BrCH2Br (1,2-dibromoethane) The double bond breaks and a bromine atom adds to each carbon. This reaction is used as a test for unsaturation: bromine water decolourises when added to an alkene.


Question 21 The process of converting long-chain hydrocarbons into shorter, more useful ones is called:

Options: A. Polymerisation B. Cracking C. Reforming D. Distillation

Answer: B

Solution: Cracking is the breaking down of large, less useful hydrocarbon molecules into smaller, more useful ones. It can be thermal cracking (high temperature and pressure) or catalytic cracking (using a catalyst at lower temperatures). Polymerisation is the opposite process: joining small molecules to form large ones.


Question 22 The product of the reaction between ethanoic acid and ethanol in the presence of concentrated H2SO4 is:

Options: A. Ethanol B. Ethyl ethanoate C. Diethyl ether D. Ethane

Answer: B

Solution: This is an esterification reaction: CH3COOH + C2H5OH -> CH3COOC2H5 + H2O (Ethanoic acid + Ethanol -> Ethyl ethanoate + Water) Concentrated H2SO4 acts as a catalyst and dehydrating agent. The ester (ethyl ethanoate) has a fruity smell. This reaction is reversible.


Environmental Chemistry

Question 23 The gas primarily responsible for acid rain is:

Options: A. Carbon dioxide B. Nitrogen C. Sulphur dioxide D. Oxygen

Answer: C

Solution: Sulphur dioxide (SO2) is the primary cause of acid rain. It dissolves in rainwater to form sulphurous acid (H2SO3), which can be further oxidised to sulphuric acid (H2SO4). Nitrogen oxides (NOx) also contribute to acid rain, forming nitric acid (HNO3). Carbon dioxide dissolves in water to form weak carbonic acid, which is responsible for normal (slightly acidic) rain, not acid rain.


Qualitative Analysis

Question 24 When sodium hydroxide solution is added to a solution containing Fe^3+ ions, the precipitate formed is:

Options: A. White B. Green C. Reddish-brown D. Blue

Answer: C

Solution: Fe^3+ + 3OH- -> Fe(OH)3 (reddish-brown precipitate) This precipitate is insoluble in excess NaOH. For comparison: Fe^2+ gives a dirty green precipitate, Cu^2+ gives a light blue precipitate, and Zn^2+ and Al^3+ give white precipitates that dissolve in excess NaOH.


Question 25 A gas that turns acidified potassium dichromate paper from orange to green is:

Options: A. Carbon dioxide B. Hydrogen sulphide C. Sulphur dioxide D. Ammonia

Answer: C

Solution: Sulphur dioxide (SO2) is a reducing agent. It reduces the orange dichromate(VI) ions (Cr2O7^2-) to green chromium(III) ions (Cr^3+). This colour change from orange to green is the confirmatory test for SO2 gas.


How to Score A1 to B3 in WAEC Chemistry

Strategy 1: Master Stoichiometric Calculations

Mole calculations are the backbone of Chemistry. Ensure you can convert between mass, moles, volume of gas, and concentration of solution fluently. Practise at least 10 stoichiometry problems daily until the process becomes automatic.

The mole calculation flowchart:

  • Given mass? Divide by molar mass to get moles
  • Given gas volume? Divide by molar volume (22.4 at STP, 24.0 at room temp) to get moles
  • Given solution concentration and volume? Multiply to get moles
  • Given moles? Use the balanced equation ratio to find moles of any other substance
  • Need mass? Multiply moles by molar mass
  • Need gas volume? Multiply moles by molar volume
  • Need concentration? Divide moles by volume

Strategy 2: Memorise Key Equations and Reactions

You must know the equations for common reactions: neutralisation, combustion, decomposition, displacement, redox, esterification, and industrial processes (Haber, Contact, Solvay). Write out 10 equations per day from memory and check them against your textbook.

Strategy 3: Build a Qualitative Analysis Reference Sheet

The alternative-to-practical paper tests your knowledge of confirmatory tests for gases, cations, and anions. Create a reference table (similar to the one in this guide) and review it daily. Know what reagent to add, what observation to expect, and what conclusion to draw.

Strategy 4: Understand Organic Chemistry Systematically

Organic chemistry has a logical structure. Learn it in order: alkanes, alkenes, alkynes, alcohols, carboxylic acids, esters. For each class, know the general formula, naming convention, functional group, characteristic reactions, and at least one preparation method.

Homologous SeriesGeneral FormulaFunctional GroupKey Reaction Type
AlkanesCnH2n+2None (C-C, C-H only)Substitution, combustion
AlkenesCnH2nC=C double bondAddition
AlkynesCnH2n-2C triple bond CAddition
AlkanolsCnH2n+1OH-OHOxidation, esterification, dehydration
Alkanoic acidsCnH2n+1COOH-COOHEsterification, neutralisation
EstersCnH2n+1COOCmH2m+1-COO-Hydrolysis

Strategy 5: Study the Periodic Table Actively

Do not just memorise where elements are. Understand the trends: why ionisation energy increases across a period, why atomic radius increases down a group, why electronegativity decreases down a group. When you understand the reason for a trend, you can predict properties of elements you have not specifically studied.

Strategy 6: Practise Under Exam Conditions

Solve complete past papers under timed conditions. Paper 1: 50 questions in 60 minutes. Paper 2: 5 theory questions in 90 minutes. This builds the speed and accuracy you need on exam day.

Free Practice: SchoolHub's JAMB CBT App offers Chemistry questions in CBT format with timer, instant scoring, and explanations.


Topic-by-Topic Study Plan (12 Weeks)

WeekTopicsStudy Focus
1Separation Techniques; Atomic StructurePurification methods, electronic configuration, isotopes
2Chemical Bonding; Periodic TableBond types, molecular shapes, periodic trends
3Stoichiometry and Mole ConceptMolar mass, reacting masses, gas volumes, solution concentration
4States of Matter; Gas LawsKinetic theory, Boyle's/Charles's law, ideal gas equation
5Acids, Bases, and SaltsDefinitions, pH, neutralisation, salt preparation, solubility
6Redox Reactions; ElectrochemistryOxidation states, electrolysis, Faraday's laws
7Energy Changes; Rates and EquilibriumEnthalpy, Hess's law, Le Chatelier's principle, Kc
8Non-metals and Their CompoundsH2, O2, N2, S, halogens, industrial processes
9Metals and Their CompoundsReactivity series, extraction, alloys, transition metals
10Organic ChemistryHydrocarbons, functional groups, reactions, petrochemicals
11Qualitative Analysis; Environmental ChemistryGas tests, cation/anion tests, pollution, acid rain
12Full Revision + Mock Exams3 complete past papers under timed conditions

Daily routine: 1 hour of theory + 1 hour of calculations, equations, and past questions.


Common Mistakes in WAEC Chemistry (and How to Avoid Them)

Mistake 1: Not Balancing Equations

An unbalanced equation gives wrong stoichiometric ratios, leading to wrong answers in calculations. Always check that the number of atoms of each element is equal on both sides of the equation before using it in calculations.

Mistake 2: Confusing Molar Volume Values

At STP (0 degrees C, 1 atm), the molar volume of a gas is 22.4 dm^3. At room temperature (25 degrees C, 1 atm), it is approximately 24.0 dm^3. Using the wrong value leads to incorrect answers. Always check which temperature condition the question specifies.

Mistake 3: Forgetting to Convert Units

Common unit errors: using cm^3 instead of dm^3 (divide by 1000), using grams instead of kilograms, or forgetting to convert temperature to Kelvin for gas law calculations. Always check your units before substituting values.

Mistake 4: Mixing Up Oxidation and Reduction

Remember: Oxidation Is Loss (of electrons), Reduction Is Gain (of electrons). Use the mnemonic OIL RIG. If a substance loses electrons, it is oxidised. If it gains electrons, it is reduced. The substance that is oxidised is the reducing agent, and vice versa.

Mistake 5: Not Knowing Qualitative Analysis Tests

Many candidates lose marks on the practical/alternative-to-practical paper because they do not know the confirmatory tests for common gases, cations, and anions. Memorise the tests table in this guide and practise applying them to unknown samples.

Mistake 6: Ignoring Organic Chemistry

Organic chemistry accounts for about 12% of the syllabus and appears in both Paper 1 and Paper 2. Some candidates find it difficult and skip it. This is a mistake, as the questions are often straightforward if you know the naming conventions and key reactions.


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Frequently Asked Questions

What is the hardest topic in WAEC Chemistry?

Electrochemistry (Faraday's law calculations) and organic chemistry are considered the most challenging by many students. However, both become manageable with systematic study. Break electrochemistry into steps (calculate charge, apply Faraday's law), and learn organic chemistry by homologous series.

How many equations do I need to memorise?

You should know approximately 30 to 40 key equations, including common reactions (neutralisation, combustion, displacement, decomposition), industrial processes (Haber, Contact, Solvay), and organic reactions (addition, substitution, esterification, polymerisation). Write them out daily until they are automatic.

Is WAEC Chemistry harder than JAMB Chemistry?

WAEC Chemistry is more demanding because it includes a theory paper and a practical/alternative-to-practical paper. JAMB is entirely objective. However, the content is similar, so thorough WAEC preparation also prepares you well for JAMB.

How should I prepare for the practical paper?

Study the qualitative analysis tests for gases, cations, and anions. Practise recording observations in the correct format (test, observation, inference). Learn how to perform titration calculations. If your school has a chemistry laboratory, attend every practical session.

Do I need a scientific calculator for WAEC Chemistry?

A non-programmable scientific calculator is allowed. Make sure you can use it for logarithms, powers, and standard form calculations. Most WAEC Chemistry calculations can be done with simple arithmetic, but a calculator helps with more complex problems.

What are the most common calculation types in WAEC Chemistry?

Mole-mass-volume conversions, concentration and dilution, empirical/molecular formula determination, enthalpy calculations using Hess's law or bond energies, electrolysis (Faraday's law), and gas law calculations appear most frequently.

Can I pass WAEC Chemistry without understanding organic chemistry?

You can pass, but you are unlikely to score highly. Organic chemistry accounts for about 12% of the syllabus, and questions appear in both Papers 1 and 2. Learning the naming conventions, functional groups, and key reactions is worth the effort.

How many past papers should I solve?

Aim for at least 5 to 10 complete past papers (Papers 1 and 2). Solve them under timed conditions. Review every question you got wrong, understand the solution, and note the topic area so you can revise it further.


Start Practising WAEC Chemistry Today

Chemistry rewards methodical, consistent preparation. Every equation you memorise, every calculation you practise, and every qualitative test you learn brings you closer to a strong grade. Start early and build your skills across all three dimensions: conceptual understanding, calculation ability, and memorisation.

Your action plan:

  1. Bookmark this guide and use the syllabus breakdown as your study checklist
  2. Work through the 25 practice questions above with pen and paper, showing all working
  3. Create an equation sheet and a qualitative analysis table, and review them daily
  4. Get 5 to 10 years of WAEC Chemistry past papers and work through them systematically
  5. Visit SchoolHub's JAMB CBT Practice App for daily Chemistry objective practice
  6. Follow the 12-week study plan to cover every topic
  7. Practise mole calculations every single day until they become second nature

Free Practice: SchoolHub's CBT Practice Platform is completely free. Open it now and start building your Chemistry skills.


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